Talk:Negabinary

how are negative and positive numbers represented?

(--Tarquin)

I assume the value of the digit n, counting from digit 0 on the right, is (-2)ⁿ, and guessing that each digit can be 0 or 1. (If each digit can be 0 or -1, it wouldn't make much difference.)

So the number d_x...d₂d₁d₀, where d_something is a digit 0 or 1, would be

\sum _{n=0}^{x}d_{n}(-2)^{n}

.

-11101100101010101101 would then be 110100101111111100111.

I haven't actually looked any of this up anywhere, or heard it anywhere, just seemed likely. كسيپ Cyp 17:29 2 Jun 2003 (UTC)

That is correct according to MathWorld: http://mathworld.wolfram.com/Negabinary.html --Cessen 07:46, 6 May 2005 (UTC)[reply]

Counting

When at the counting section, the numbers go:

0 1 110 111 100

Is this correct?

Time discrepancy

The Polish-named guy independently discovered it 9 years after two Polish computers were designed to use it. Sounds unlikely. Can someone re-research that please?